Answer
x=$\frac{-3}{2}$, -1
Work Step by Step
The quadratic formula states that if a$x^{2}$+bx+c=0, and a$\ne$0, then
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. If
2$x^{2}$+5x+3=0, then a=2, b=5, and c=3, and to solve for x, then all we must do is plug the numbers into the quadratic formula then simplify.
$x=\frac{-5\pm\sqrt{(5)^2-4(2)(3)}}{2(2)}$
=$\frac{-5\pm\sqrt{25-24}}{4}$ (5 squared=25, 4*2*3=24, and 2*2=4)
=$\frac{-5\pm\sqrt{1}}{4}$ (25-24=1)
=$\frac{-5\pm1}{4}$ ($\sqrt 1$=1)
Since there is a plus minus symbol, we of course need to make sure that we compute both of our answers.
x=$\frac{-5+1}{4}$=$\frac{-4}{4}$=-1
x=$\frac{-5-1}{4}$=$\frac{-6}{4}$=$\frac{-3}{2}$
