Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Practice and Problem-Solving Exercises - Page 565: 45

Answers may vary. $2x^2+12x-14=0$ $x=1, -7$

$2x^2+12x-14=0$ $(2x^2+12x-14)/2=0/2$ $x^2+6x-7=0$ $x^2+6x-7+(6/2)^2+7=(6/2)^2+7$ $x^2+6x+9 = 16$ $(x+3)^2 = 16$ $\sqrt {x+3}^2 = \sqrt {16}$ $x+3 = 4$ or $x+3 = -4$ $x=1, -7$