Answer
a) completing the square
b) finding square roots
Work Step by Step
a)
$k^2-3k=304$
$k^2-3k+(3/2)^2=304+(3/2)^2$
$k^2-3k+9/4 = 304+ 9/4$
$k^2-3k+9/4 = 1216/4+9/4$
$(k-3/2)^2 = 1225/4$
$\sqrt {(k-3/2)^2)} = \sqrt {1225/4}$
$(k-3/2) = ±35/2$
$k-3/2 = 35/2$
$k=38/2$
$k=19$
$k-3/2 = -35/2$
$k = -32/2$
$k=-16$
b)
$t^2-6t+16=0$
$b^2-4ac$
$(-6)-4*1*16$
$36-64$
$-28$
There are no solutions for this equation (since the discriminant is negative).
