Answer
$x = 1, -1, -5$
Work Step by Step
$x^3+5x^2-x-5=0$
$x^3-x+5x^2-5=0$
$x(x^2-1)+5(x^2-1)=0$
$(x+5)(x^2-1)=0$
$(x+5)(x-1)(x+1)=0$
$x+5=0$
$x+5-5 =0-5$
$x = -5$
$x+1=0$
$x+1-1 =0-1$
$x = -1$
$x-1=0$
$x-1+1 =0+1$
$x = 1$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 559: 43
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