Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Standardized Test Prep - Page 553: 62

a) 4 ft b) The surface area increases by a multiple of 4 to 384$ft^2$.

a) surface area = 96 $ft^2$ $A = 2*wh+2*wl+2*hl$ $96 = 6*s^2$ $96/6 = 6*s^2/6$ $16 = s^2$ $\sqrt {16} = \sqrt {s^2}$ $s = 4$ b) $A = 2*wh+2*wl+2*hl$ $A = 2*8*8+2*8*8+2*8*8$ $A = 128*3$ $A = 384$