Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 551: 25

No Solution

First you subtract 12 from both sides $$3a^2 = -12$$ Then you divide 3 from both sides $$a^2 = -3$$ The next step is to find the square root of both sides but since there is a negative on the right side of the equation, there is no solution because you can't have a negative under a square root.