Answer
$(7b^{3}+1)(b-2)$
Work Step by Step
$7b^{4} - 14b^{3} + b - 2$
Factor by grouping, group the first two terms and last two terms together.
$(7b^{4} - 14b^{3}) + (b - 2)$
Factor out the common factors from both parenthesis.
$7b^{3}(b-2) +1(b-2)$
We take (b-2) and factor it out which gives us.
$(7b^{3}+1)(b-2)$
