Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Get Ready - Page 471: 23

Answer

$p^2q^3$

Work Step by Step

We start with the given expression: $\frac{p^4q^9}{p^2q^6}$ To divide powers with the same base, we subtract the exponents: ${p^{4-2}}q^{9-6}=p^2q^3$
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