Answer
$(6h-1)^{2}$
Work Step by Step
Given the polynomial
$(6h)^{2}$ - 12h + $(1)^{2}$
We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of
$a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$
In this polynomial a= 6h and b=1
$(6h)^{2}$ - 2(6h)(1) + $(1)^{2}$ = $(6h-1)^{2}$