Answer
5r(r+3)($2r^{2}$+1)
Work Step by Step
Given the polynomial
$10r^{4}$ + $30r^{3}$ + $5r^{2}$ + 15r
We see that the terms have a common factor of 5r so we factor out a 5r.
5r($2r^{3}$ + $6r^{2}$ + r + 3)
We take the GCD of the first two and the GCD of the last two terms.
5r ($2r^{2}$(r+3)+1(r+3))
We take (r+3) and factor it out which gives us.
5r(r+3)($2r^{2}$+1)
