Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 519: 19

$(5v+6)(4v^{2}-5)$

$20v^{3}=$$2.2.5.v.v.v$ and $24v^{3}=$$2.2.2.3.v.v.v$ Hence , $GCF=2.2.v.v=4v^{2}$ $25v=5.5.v$ and $30=2.3.5$ Hence, $GCF=5$ After grouping : $=(20v^{3}+24v^{2})-(25v+30)$ $=4v^{2}(5v+6)-5(5v+6)$ $=(5v+6)(4v^{2}-5)$