Answer
3$(6n^{3}+7)(6n^{3}-7)$
Work Step by Step
3($36n^{6}$ - 49)
We use the formula for the difference of squares to apply to this question.
The difference of squares formula is:
$(a-b) (a+b) = a^{2} - b^{2}$
= 3($36n^{6}$ - 49)
*** Take the square root of $36n^{6}$ which is $6n^{3}$. Becuase $6n^{3}$ × $6n^{3}$ = $36n^{6}$
*** Take the square root of 49 which is 7. Becuase 7 × 7= 49
= $(6n^{3})^{2}−7^{2}$
In the given formula let $6n^{3}$ represents a and 7 represents b.
3($(6n^{3})^{2}−7^{2}$) = 3$(6n^{3}+7)(6n^{3}-7)$
