Answer
(d-10)(d-10)
Work Step by Step
Given the polynomial
$d^{2}$ - 20d + 100
*** We break of the middle term into two factors that add to give -20 and multiply to give +100. The two numbers are -10 and -10.
$d^{2}$ - 10d - 10d + 100
We take the GCD of the first two and the GCD of the last two terms.
d(d-10) -10(d-10)
We take (d-10) and factor it out which gives us.
(d-10)(d-10)
