Answer
$(3d+2)(d+7)$
Work Step by Step
Rewrite 23d as 21d + 2d
$3d^{2} + 23d + 14 = 3d^{2} + 21d + 2d +14$
Factor out GCF of each pair of terms, which would be
$3d(d+7) + 2(d+7)$
Now use distributive property =
$(3d+2)(d+7)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 508: 9
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