Answer
$(n-7)$ and $(n+4)$ are the dimensions
Work Step by Step
$n^2-3n-28$
$n^2-3n-28 = n^2-7n+4n-28$
$n^2-7n+4n-28 = (n-7)(n+4)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Lesson Check - Page 503: 5
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