Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-3 Multiplying Binomials - Practice and Problem-Solving Exercises - Page 491: 49

Answer

$24c^{4}+72c^{2} + 54$

Work Step by Step

The surface area of a cube can be found using the equation: A=6$L^{2}$ A side length of the cube is 2$c^{2}$+3 and we substitute it into the equation above. A=6$(2c^{2}+3)^{2}$ We use the rule of (a+b)^{2} = a^{2} + 2ab + b^{2} for $(2c^{2}+3)^{2}$ A=6($(2c^{2})^{2}+2(2c^{2})(3) + 3^{2}$) A=6($4c^{4}+12c^{2} + 9$) We distribute the 6 into the parenthesis. A=$24c^{4}+72c^{2} + 54$
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