Answer
$\frac{mq^2}{n^4}$
Work Step by Step
We rewrite the given expression as a division problem: $mn^{-4}\div p^0q^{-2}$
The zero as an exponent rule states that for every nonzero number $a$, $a^0=1$. Since $p^0=1$, and anything multiplied by $1$ is itself, we can ignore the $p^0$ term: $mn^{-4}\div q^{-2}$
The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression: $\frac{m}{n^4}\div\frac{1}{q^2}$
To divide fractions, we multiply by the reciprocal: $\frac{m}{n^4}\times\frac{q^2}{1}$
To multiply the fractions, we multiply the numerators and the denominators: $\frac{mq^2}{n^4}$
