Answer
$h^{26}/32y^9$
Work Step by Step
$2y^{-9}h^2(2y^0h^{-4})^{-6}$
$2/y^9*h^2*(2*h^{-4})^{-6}$
$2/y^9*h^2*1/2^6*h^{24}$
$h^{26}/y^9*2^5$
$h^{26}/32y^9$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - Chapter Test - Page 467: 4
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