Answer
$-4/3*r^6*z^{-8}$
Work Step by Step
$(-2r^{-4})^2*(-3r^2*z^8)^{-1}$
$((-2)^2*(r^{-4})^2*-3^{-1}*(r^2)^{-1}*(z^8)^{-1}$
$4*r^{-8}*-1/3*r^{-2}*z^{-8}$
$-4/3*r^{8-2}*z^{-8}$
$-4/3*r^6*z^{-8}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - Chapter Review - 7-3 and 7-4 Multiplication Properties of Exponents - Page 465: 38
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