Answer
$n^{15}$
Work Step by Step
$(7^0n^{-3})^2(n^7)^3$
$(1/n^6)*n^{21}$
$n^{21}/n^6$
$n^{21-6}$
$n^{15}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Mixed Review - Page 446: 102
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