Answer
$\dfrac{1}{a+b}$
Work Step by Step
(i) $x^m \cdot x^n = x^{m+n}$
(ii) $x^{-m} = \dfrac{1}{x^m}, x \ne 0$
Use rule (i) above to obtain:
$=(a+b)^{2+(-3)}
\\=(a+b)^{-1}$
Use rule (ii) above to obtain:
$=\dfrac{1}{a+b}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-3 Multipying Powers with the Same Base - Practice and Problem-Solving Exercises - Page 431: 68
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