Answer
$\frac{5s^2}{t}$
Work Step by Step
We want to simplify $5s^2t^{-1}$.
The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$.
Thus, we can rewrite $t^{-1}$ as $\frac{1}{t}$ and put the $t$ on the denominator of the expression, giving us $\frac{5s^2}{t}$
