Answer
Solution:($\frac{7}{10}$,$\frac{-4}{5}$)
Work Step by Step
Given: 4x+y=2 and 3y+2x=-1
3(4x+y=2)=12x+3y=6
(12x+3y)-(3y+2x)=6-(-1) (Subtract two equations)
12x+3y-3y-2x=7 (Simplify)
12x-2x=7 (Simplify)
10x=7
x=$\frac{7}{10}$ (Divide both sides by 10)
Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$
Solution ($\frac{7}{10}$,$\frac{-4}{5}$)
