Answer
($-\frac{88}{38}$, $-\frac{29}{19}$)
Work Step by Step
Our first two equations:
1. 3x+2y=-10
2. 2x-5y=3
First lets multiply the first equation by 2 and the second equation by 3.
1. 2(3x+2y=-10)
2. 3(2x-5y=3)
=
1. 6x+4y=-20
2. 6x-15y=9
Now subtract the second equation from the first equation. We get:
19y=-29 (Divide by 19 on both sides)
y=$-\frac{29}{19}$
Now lets plug this into the second equation to find the value of x.
2x-5($-\frac{29}{19}$)=3
2x+$\frac{145}{19}$=3 (Subtract (145/19) from both sides of the equation)
2x=$-\frac{88}{19}$. (Divide by 2 to both sides)
x=$-\frac{88}{38}$
So our solution is: ($-\frac{88}{38}$, $-\frac{29}{19}$)
