Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Lesson Check - Page 377: 2

Answer

(1,4)

Work Step by Step

Multiply the first equation by 2. Add the equations to eliminate q. $3p+q\ \ =\ \ 7\ \ \ \ $ multiply by 2 $\ \ \ \ 6p+2q=\ 14$ $2p-2q=-6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{2p-2q=-6}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8p\ \ \ \ \ \ \ \ \ =\ \ 8$ Solve for p. $8p=8$ $8p\div8=8\div8$ $p=1$ Substitute 1 for p in either equation. $3p+q=7$ $3(1)+q=7$ $3+q-3=7-3$ $q=4$
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