Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 371: 21

$x=0$ , $y=-\frac{1}{2}$

#$1$ Equations $x=2y+1$ $7x-2y=1$ Substitude x in to 2nd equation and solve for y $7(2y+1)-2y=1$ $14y+7-2y=1$ $12y+7=1$ ........-7........-7 $12y=-6$ $12y\div12 = -6\div12$ $y= -\frac{1}{2}$ substitude y into 1st equation and solve for x $x = 2(-\frac{1}{2}) +1$ $x= -\frac{2}{2}+1$ $x=-1+1$ $x=0$ The answers are $x=0$ , $y=-\frac{1}{2}$