Answer
$y-2 = x-1$
$y = x + 1$
Work Step by Step
given: (-2, -1) and (1, 2)
$y-y_{1} = m*(x-x_{1})$
$m = (2--1)/(1--2)$
$m = 3/3 = 1$
$y-y_{1} = m*(x-x_{1})$
$y-2 = x-1$
$y-2 = x-1$
$y-2+2 = x-1+2$
$y = x + 1$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 5 - Linear Functions - 5-5 Standard Form - Mixed Review - Page 326: 73
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