Answer
$y-2=-\frac{5}{3}(x-4)$
Work Step by Step
The point-slope form of an equation of a non-vertical line with slope $m$ and through point $(x_1,y_1)$ is $y-y_1=m(x-x_1)$
We plug in $4$ for $x_1$, $2$ for $y_1$, and $-\frac{5}{3}$ for $m$ to get the equation:
$y-2=-\frac{5}{3}(x-4)$