Answer
No, y-4=3(x+1) is not an equation of a line through (-2, 1)
Work Step by Step
y-4=3(x+1) is not an equation of a line through (-2, 1) because a point is written in the form (x, y), so if the point (-2, 1) was on the graph of
y-4=3(x+1), then when you plugged in -2 for x and 1 for y the equation would be equalivalent
1-3=3(-2+1)
-2=3(-1)
-2$\ne$-3
Since -2 is not equal to -3, the point (-2, 1) doesn't exist on the graph of the equation y-4=3(x+1)
