Answer
$y=1\frac{1}{3}$ OR $y=-2\frac{2}{3}$
Work Step by Step
$3|3y+2|=18\longrightarrow$ divide each side by 3
$3|3y+2|\div3=18\div3\longrightarrow$ divide
$|3y+2|=6\longrightarrow$ definition of absolute value
$3y+2=6$ OR $3y+2=-6\longrightarrow$ subtract 2 from all parts
$3y+2-2=6-2$ OR $3y+2-2=-6-2\longrightarrow$ subtract
$3y=4$ OR $3y=-8\longrightarrow$ divide all parts by 3
$3y\div3=4\div3$ OR $3y\div3=-8\div3\longrightarrow$ divide
$y=1\frac{1}{3}$ OR $y=-2\frac{2}{3}$
