Chapter 3 - Solving Inequalities - 3-7 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 211: 35

$y\leq-11$ or $y\geq-5$

We are given $|y+8|\geq3$ This is an absolute value inequality which could be written as: $y+8\geq3$ or $y+8\leq-3$ First solution: $y+8\leq-3$ $y+8-(8)\leq-3-(8)$ $y\leq-11$ Second solution: $y+8-(8)\geq3-8$ $y\geq-5$