Answer
$b\lt-1$ or $b\gt2$
Work Step by Step
$6b-1\lt-7\longrightarrow$ add 1 to each side
$6b-1+1\lt-7+1\longrightarrow$ add
$6b\lt-6\longrightarrow$ divide each side by 6
$6b\div6\lt-6\div6\longrightarrow$ divide
$b\lt-1$
OR
$2b+1\gt5\longrightarrow$ subtract 1 from each side
$2b+1-1\gt5-1\longrightarrow$ subtract
$2b\gt4\longrightarrow$ divide each side by 2
$2b\div2\gt4\div2\longrightarrow$ divide
$b\gt2$
Since -1 and 2 are not included in the solution sets, the endpoints on the graph are open circles.
