Answer
3
Work Step by Step
$\frac{2d-3}{5}\longrightarrow$ substitute 9 for d
=$\frac{2(9)-3}{5}\longrightarrow$ multiply
=$\frac{18-3}{5}\longrightarrow$ subtract
=$\frac{15}{5}\longrightarrow$ divide
=$3$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 3 - Solving Inequalities - 3-5 Working with Sets - Mixed Review - Page 199: 63
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