Answer
Not equivalent
Work Step by Step
$n-\frac{1}{4}\lt\frac{5}{4}$ : add $\frac{1}{4}$ to each side
$n-\frac{1}{4}+\frac{1}{4}\lt\frac{5}{4}+\frac{1}{4}$ : simplify
$n\lt\frac{6}{4}$
This is not equivalent to $n\lt1$.
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