Answer
$F=\frac{9}{5}C+32$
Work Step by Step
We are trying to isolate the variable $F$ in $C=\frac{5}{9}(F-32)$.
First, we multiply both sides by $\frac{9}{5}$, the reciprocal of $\frac{5}{9}$: $\frac{9}{5}C=F-32$
Then, we add $32$ to both sides to isolate the $F$: $F=\frac{9}{5}C+32$
