Answer
Min=25
Q1=30.5
Median=90
Q3=102.5
Max=112
Work Step by Step
You have the values:25,29,32,34,90,93,97,108,112
The minimum is the smallest value in the data which is 25.
The median is the middle value which is 90.
The maximum is the largest value which is 112.
The first quartile is the middle value between the minimum and the median(25,29,32,34). The middle values are 29 and 32 so you find their average (29+32) ÷2=30.5.The first quartile is 30.5.
The third quartile is the middle value between the median and the maximum(93,97,108,112). The middle values are 97 and 108 so you find their average (97+108)÷2=102.5. The third quartile is 102.5.
Min=25. Q1=30.5.Median=90.Q3=102.5.Max=112
