Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 770: 44

a) $1/36$ b) $1/36$ c) $1/6$

The numbers on each number cube are $1, 2, 3, 4, 5,$ and $6$. a) P(red 1 and yellow 1) $1/6 * 1/6 = 1/36$ b) P(red 2 and yellow 2) $1/6 * 1/6 = 1/36$ c) P(red 1 and yellow 1) + P(red 2 and yellow 2) + P(red 3 and yellow 3) + P(red 4 and yellow 4) + P(red 5 and yellow 5) + P(red 6 and yellow 6) $1/6 * 1/6 + 1/6 * 1/6 + 1/6 * 1/6 + 1/6 * 1/6 + 1/6 * 1/6 + 1/6 * 1/6$ $1/36 + 1/36 + 1/36 + 1/36 + 1/36 + 1/36$ $6/36 = 1/6$