Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 769: 31

1/12

You do not replace the coins, so the events are dependent: P(dime)=$\frac{3}{9}$=$\frac{1}{3}$ -3 of the 9 coins are dimes- P( penny after dime)=$\frac{2}{8}$=$\frac{1}{4}$ -2 of the 8 remaining coins are pennies- Probability: P(dime then penny)=P(dime) $\times$ P(penny after dime) P(dime then penny)=$\frac{1}{3}$ $\times$ $\frac{1}{4}$ P(dime then penny)=$\frac{1}{12}$