Answer
35
Work Step by Step
$7C3$
$7!/3!(7-3)!$
$7!/3!4!$
$(7*6*5*4!)/(4!*3*2*1)$
$(7*6*5)/(3*2*1)$
$7*5$
$35$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Lesson Check - Page 753: 6
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