Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - 12-3 Measures of Central Tendency and Dispersion - Practice and Problem-Solving Exercises - Page 731: 34

Answer

All four of the numbers would be divided by the non-zero number.

Work Step by Step

Let an example set be the following: $1, 4, 6, 7, 8, 8, 8, 9, 10, 12$ Mean = 8 (appears three times) Median = 8 (see below) Range = 11 ($12-1$) Average = 7.3 (see below) $1, 4, 6, 7, 8, 8, 8, 9, 10, 12$ $4, 6, 7, 8, 8, 8, 9, 10$ $6, 7, 8, 8, 8, 9$ $7, 8, 8, 8$ $8, 8$ $1+4+6+7+8+8+8+9+10+12$ $5 + 13 + 24 + 9 +22$ $18+33 + 22 = 73$ $73/10 = 7.3$ If we divide each of the terms by the same non-zero number (say 2, as an example), we would have the following set: $.5, 2, 3, 3.5, 4, 4, 4, 4.5, 5, 6$ Mean = 4 (appears three times) Median = 4 (see below) Range = 5.5 ($6-.5$) Average = 3.65 (see below) $.5, 2, 3, 3.5, 4, 4, 4, 4.5, 5, 6$ $2, 3, 3.5, 4, 4, 4, 4.5, 5$ $3, 3.5, 4, 4, 4, 4.5$ $3.5, 4, 4, 4$ $4, 4$ $.5, 2, 3, 3.5, 4, 4, 4, 4.5, 5, 6$ $2.5 + 6.5 + 12 + 15.5$ $36.5/10 = 3.65$
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