Answer
$x=-\frac{3}{2}$
Work Step by Step
Given: $2x^2+x-3=0$
$2x^2-2x+3x-3=0$
$(2x+3)(x-1)=0$
Solutions are: $x=1, -\frac{3}{2}$
Thus, the negative solution of $x=-\frac{3}{2}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - Cumulative Test Prep - Gridded Response - Page 710: 21
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