Answer
$\frac{-4k-61}{(k-4)(k+10)}$
Work Step by Step
$\frac{k-11}{k^2+6k-40}-\frac{5}{k-4}$
$\frac{k-11}{(k-4)(k+10)}-\frac{5}{k-4}$
$\frac{k-11}{(k-4)(k+10)}-(\frac{5}{k-4}*\frac{(k+10)}{(k+10)})$
$\frac{k-11}{(k-4)(k+10)}-(\frac{5(k+10)}{(k-4)(k+10)})$
$\frac{k-11}{(k-4)(k+10)}-(\frac{5k+50}{(k-4)(k+10)})$
$\frac{k-11-5k-50}{(k-4)(k+10)}$
$\frac{-4k-61}{(k-4)(k+10)}$