Answer
$\frac{4c+11}{3c+1}$
Work Step by Step
$\frac{\frac{7}{c+1}+4}{3-\frac{2}{c+1}}$
$\frac{\frac{7}{c+1}+4(c+1/c+1)}{3(c+1/c+1)-\frac{2}{c+1}}$
$\frac{\frac{7}{c+1}+(4c+4)/(c+1)}{(3c+3)/(c+1)-\frac{2}{c+1}}$
$\frac{\frac{4c+11}{c+1}}{\frac{3c+1}{c+1}}$
$\frac{4c+11}{3c+1}$