Answer
$ \frac{1}{n+2}$
Work Step by Step
Since we already have common denominators, we can add and simplify the numerators:
$\frac{n}{n^2 + 4n + 4} + \frac{2}{n^2 + 4n + 4} =\frac{n+2}{n^2 + 4n + 4}$
We now need to factor the denominator to see if there are any common factors:
$\frac{n+2}{n^2 + 4n + 4} = \frac{n+2}{(n+2)(n+2)}$
$(n+2)$ will cancel from the numerator and denominator:
$ \frac{n+2}{(n+2)(n+2)} = \frac{1}{n+2}$
