Answer
Choice $D$
Work Step by Step
Factoring the $GCF=x$, the given expression is equivalent to
$$
x(x^2-4)
.$$
Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of two squares, the expression above is equivalent to
$$
x(x^2-2^2)=x(x+2)(x-2)
.$$Therefore, the factors of the given expression are $x$, $(x+2)$, and $(x-2)$. Hence, Choice $D$.