Answer
$3a-5$
Work Step by Step
Given: $(-16a-15+15a^2) \div (3+5a)$
Apply long division method.
Thus, $\dfrac{(-16a-15+15a^2)}{(3+5a)}=\dfrac{15a^2}{(3+5a)}-\dfrac{-16a}{(3+5a)}+\dfrac{-15}{(3+5a)}$
$=\dfrac{15a^2}{(3+5a)}-\dfrac{-16a}{(3+5a)}+\dfrac{-15}{(3+5a)}$
$=3a-5$