Answer
$132.96
Work Step by Step
The monthly payment, $m$, is given by the function below.
$$m=\frac{A(\frac{r}{12})(1+\frac{r}{12})^n}{(1+\frac{r}{12})^n-1}$$
The loan is 3000 at 6% annual interest paid over 24 months, so these numbers can be plugged into $A$, $r$, and $n$ respectively. Be sure to convert $r$ into its decimal form.
$$m=\frac{3000(\frac{0.06}{12})(1+\frac{0.06}{12})^{24}}{(1+\frac{0.06}{12})^{24}-1} = 132.96$$
