Answer
$\frac{w^2-9}{4}$
Work Step by Step
$(w^2-8w+15)*\frac{w+3}{4w-20}$
$(w-3)(w-5)*\frac{w+3}{4(w-5)}$
$(w-3)*\frac{w+3}{4}$
$\frac{w^2-9}{4}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 662: 28
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