Answer
$\frac{-1}{x+3}$ ; x $\neq$ 3, x $\neq$ 5
Work Step by Step
(x-3) (x-5). Begin by factoring the denominator
$\frac{x-5}{(x+3)(x-5)}$ plug the factored denominator in. The (x-5) cancels out in numerator and denominator.
Equating with zero, we consider the two equations.
First, x-5=0, so x=5
Second, x-3=0, so x=3
Hence, $\frac{-1}{x+3}$ ; x $\neq$ 3, x $\neq$ 5 is the final answer.
