Answer
Please see the graph.
Work Step by Step
$y=2x^2+3$
vertex
$x=-b/2a$
$x=-0/2*2$
$x=0$
$y=2x^2+3$
$y=2*0^2+3$
$y=2*0+3$
$y=0+3=3$
$(0,3)$
One other point on the curve
$x=1$
$y=2x^2+3$
$y=2*1^2+3$
$y=2*1+3$
$y=2+3=5$
$(1,5)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - Get Ready - Page 597: 14
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